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Rational num | Computer Science homework help

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Posted on 
August 22nd, 2023
Home Homework Help Rational num | Computer Science homework help

Define a class for rational numbers. A rational number is a number that can be represented as the quotient of two integers. For example, 1/2, 3/4, 64/2, and so forth are all rational numbers. (By ½, etc we mean the everyday meaning of the fraction, not the integer division this expression would produce in a C++ program).

Represent rational numbers as two values of type int, one for the numerator and one for the denominator. Call the class rationalNum

 

Include a constructor with two arguments that can be used to set the member variables of an object to any legitimate value. Also include a constructor that has only a single parameter of type int; call this single parameter whole_number and define the constructor so that the object will be initialized to the rational number whole_number/1. Also include a default constructor that initializes an object to 0    (that is, to 0/1).

 

Overload the input and output operators >> and <<. Numbers are to be input and output in the form 1/2, 15/32, 300/401, and so forth.  Note that the numerator, the denominator, or both may contain a minus sign, so -1/2, 15/32, -300/-400 are all possible input. The input operator, >>, reads the string 15/32 as 

 

Overload all of the following operators so that they correctly apply to the type rationalNum: ==, <, >, +, -, *, and /. 

 

Write a test program to test your class.

 

[Hints: Two rational numbers a/b and c/d are equal if a*d equals c*b. If b and d are positive numbers, a/b is less than c/d provided a*d is less than c*b. 

 

  1. (a/b + c/d) is given by:

Numerator =a*d + c*b

Denominator = b*d

 

  1. (a/b – c/d) is given by 

Numerator = a*d – c*b

Denominator = b*d

 

 

 

  1. (a/b * c/d) is given by

Numerator = a*c

Denominator = b*d

 

  1. (a/b divided by c/d) is given by

Numerator = a*d

Denominator = b*c

    ]

 

The numerators and denominators of rational numbers tend to become large, so it is better to normalize intermediate results. This is achieved by calling a method, normalize(), on the number as shown:

cout << “The sum of the two numbers is: “ << result.normalize() << endl;

 

Here’s the function that you call to normalize the number. Make it a member function of the rationalNum class. It is called in the driver program to:

 

  • Display each input number read
  • Display the results of the arithmetic operations.

 

rationalNumber rationalNumber::normalize()

{

  rationalNum temp;

  int x,y,z;

 

  x=numerator;

  y=denominator;

  z=(x*x < y*y)? (z=x):(z=y);

  for (int i=2; i*i<=z*z; i++){

    while ((x%i)==0 && (y%i)==0 )

    {

      x=x/i;

      y=y/i;

      z=z/i;

    }

  }

  if (y<0){

    temp.numerator=-x;

    temp.denominator=-y;

  }

  else {

    temp.numerator=x;

    temp.denominator=y;

  }

  return temp;

}

 

Here’s the output of test run of the driver program using rationalNum objects.

 

E:neu>rationalMain

 

Enter the first value:  2/3

 

Enter the second value: 3/5

 

value1 is                       2/3

Normalized value1:              2/3

 

value 2 is:                     3/5

Normalized value2:                      3/5

 

addition                        19/15

Normalized sum:         19/15

 

subtraction                     1/15

Normalized difference:  1/15

 

multiplication                   6/15

Normalized product:     2/5

 

division                        10/9

Normalized quotient:    10/9

 

is 2/3 < 3/5 ?  no

is 2/3 > 3/5 ?  yes

is 2/3 =  3/5 ?         no

 

Press any key to continue . . .

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